Page 160 - Electrician - TT (Volume 2)
P. 160

ELECTRICIAN - CITS




              The resultant pitch is the sum of the front and back pitches.   Y  = Y + YF
                                                                     R    B
              •  The number of coil sides must satisfy the following relations.
                 Z = P x Y  ± 2 where P is the number of poles.
                         A
              •  In the case of simplex wave winding the number of parallel paths `A’ is equal to 2 only, irrespective of
                 the number of poles. However the number of parallel paths increases in multiples of the plex of the
                 windings.

                 Eg. A = 2 x plex.
                 Considering the above points, only an armature having designated slots can be wound for
                 wave winding.

              •  Two brushes are necessary, but as many brushes as there are poles may be used, and they must be
                 set so that they short-circuit only the coils cutting no flux.
              •  The brushes must be wide enough  to cover atleast `m’ segments where ‘m’ is the ‘plex’ of the winding.
              Calculations : The following calculations are made for finding out winding pitches and coil connections
              with commutator segments for simplex wave winding.
           Example

           Number of commutator segments    7 Nos.
           Number of slots                  7 Nos.
           Number of poles                  2 Nos.
           Type of winding                  Wave.
           Winding table

           1   The number of coils  =  Number of commutator segments = 7 coils.
           2   The number of conductors or No. of coil sides  = No. of coils x 2 = 7 x 2 = 14 conductors.

                           No.of   slots
           3    Pole   pitch  Y P      No.   of   poles      7/2      3.5   slots,
                                          say     3 slots

                       No.of   conductors
              Also,  Y P       No.   of   poles       14/2       7    conductors


           4   No. of conductors/slot = 14/7 = 2 conductors/slot.  Hence, the winding is double layer.

                                  Z  2
           5   Average   pitch  Y A       P
                   14    2
                                  16/2       8    (for   progressiv e  winding).
                      2
                   14    2
                                  12/2       6    (for   retrogress ive  winding).
                      2
              Hence Y = Y = 8 or 6.
                         C
                     A
           6   Taking Y = 8 for progressive winding we have
                     A
                    2Y     = 2 x 8 = 16 = Y + Y
                    A                B  F
              Y   Y    =  2
                   F
               B
              Y + Y    = 16.
               B
                   F
              Hence back pitch Y = 9 and front pitch Y = 7.
                               B                  F
              Taking YA= 6 for retrogressive winding we have
                      2Y  = 2 x 6 = 12 = Y + Y F
                                    B
                     A
 146                                                       147

                                    CITS : Power - Electrician & Wireman - Lesson 86-92
   155   156   157   158   159   160   161   162   163   164   165