Page 304 - Mechanic Diesel - TT

Pm
LAN
x
IHP =
4500
2πNT K
BHP =
4500
MECHANIC DIESEL - CITS
FHP = IHP − BHP
Example 1: Find the IP of a four-cylinder two-stroke petrol engine from the following data.
diameter of piston = 10 cm
stroke = 15 cm
rpm = 1600 BHP
Mechanical efficiency = x100
Area of positive loop of indicator diagram = 5.76 cm² IHP

Area of negative loop of indicator diagram1600 = 0.26 cm²
Length of indicator diagram = 55 mm
Pm = W/Vs
spring constant = 3.5 bar /cm
Solution: The net area of the indicator diagram =5.76-0.265.50 cm²

Area of the diagram
Area of height =
Length of the diagram

Mean effective pressure = Mean height Number of cylinder) 11 x 4 = 44 kW. = 11 kW
Abduction 2. The diameter of the cylinder of an auto cycle gas engine is 25 cm and stroke is 45 cm.

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CITS : Automotive - Mechanic Diesel - Lesson 87 CITS : Automotive - Mechanic Diesel - Lesson 87