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P. 30

WORKSHOP CALCULATION & SCIENCE  - CITS



           Example 3
           Out of 80000 cars, which were tested on road, only 16000 cars had no fault.  What is the percentage in this
           acceptance.


                  160000        100
                =        × 100 =    =  20%
                  80000          5

           Example 4               100   1800000

                                       =
              Original

                     Price =
                           18000 ×
           The price of a motor cycle dropped to 92% of original price and now sold at Rs.18000/-  What was the original
                                   92
                                           92
           price.
           Solution         litres

                   (100 −
                                  100
                         90)
                 =   160000
                                 × 100
           Present price of Motor cycle Rs.18000
                           ×
                            100
                  =
                             100=
                                      =
                                       20%
                                   5
                    80000
           This is the value of 92% of original price
                     10
                   =    × 100
                    100              100  1800000
               Original   Price = 18000 ×  =
                                     92      92

           = Rs. 19565160000        100
                     =       × litres=  =  20%
                              100
                           90)
                     (100 −
                   =
                                     5
           Example 5 80000         × 100
                              100
           A Motor vehicle uses 100 litres of Petrol per day when travelling at 30 kmph.  After top overhauling  the consumption


           falls to 90 litres per day.  Calculate percentage of saving.
                       10
                                             1800000
                                       100
                          ×

                  Orig
                                     ×
                                           =
                    =inal
                           100 18000e =
                         Pric
           Solution   100              92       92
           Percentage of saving = Decrease in consumption/Original consumption x 100
                                litres
                     = (100 − 90)    × 100
                                 100
                         10
                       =    × 100
                        100
           = 10 % Saving in fuel.
           Assignment
           1                              a = 400mm (side of square)
                                          d  = 400 mm
                                          Wastage = ______ %.
           2                              d = 26mm
                                          ‘a’ depth of u/cut =
                                          2.4mm
                                          reduction of area at
                                          cross-section
                                          = ______ %
                                                           17

                                            CITS : WCS - Electrical - Exercise 3
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