Page 78 - WCS - Electrical

1
2
2 x S(S a)(S b)(S c) x b 2 x 15 x 3 x 7 x 5 144 60 2 2 x 15(15 2)(15 8)(15 10)
4
180
40
2
1000
20 area WORKSHOP CALCULATION & SCIENCE - CITS 4a b 2 2 x 1575 a b c
500
60

2
x
c)
a)(S
S(S
b)(S
10 base 20 50 4 3 2
3 1 15 x 2 60 x 2 6
2
30 12 8 10 S b 2 3 P 2 2 x bh Base 2 Height 2 3.5 10 2 S b 2 5 3 2
2
2
2
+
2
Perimeter of ellipse P = 2π 2 (a b2 2 ) unit 4 9 10 12 31
unit
2 1 b 2 2 4 x 5 6 2 3 S(S a)(S b)(S c) 15.5 x 6.5 x 5.5 x 3.5
2
b
9
16
25
4a
1
2
4
1 Find its area and perimeter, if the major and minor axis of an ellipse are 12 cm and 8 cm respectively. 2 15(15 2)(15 8)(15 10)
2
4
2
2
c)
x
x
7
x
x
x
15
x
2
b
3
5
2
x
b)(S
S(S
a)(S
144
60
4
Solution: 15.5(15.5 9)(15.5 10)(15.5 3.5) 1939.4375 274.91 θ r (a b 2 )
2
+
Length
b
area
2
Major axis 2a 20 = 12 cm 500 1000 2 x S(S a)(S b)(S c) 40 180 60 of arc l b 2 360 1575 x2 x2 unit a 2 c 2 unit
4a
3
4
10 12 22 20 50 2 2 22 (36 16) 22 22 2
base
(6
2 x
5.1

26 2 x
cm

x

a 30 = = 6 cm 6 x 2 4 cm 2 2 2 3 22 P 2 3 4 ) 2 1 unit 2 Base 2 2 Height unit 15 7 x 2 60 10 2 x 6 7 x S b 32.06 5 3 2
2
2
2
12
8

10

x
bh
2
7
2
7
7
b
2
S
2
Minor axis 2b 2 = 8 cm 4 2 3.5
1 2 2 1 3 9 10 12 31
2 x S(S a)(S b)(S c) x b 2 x 15 x 3 x 7 x 5 144 60 2 x 15(15 2)(15 8)(15 10) 1 b 2 2 4 x 5 2 6 2 2 S(S a)(S b)(S c) 15.5 x 6.5 x 5.5 x 3.5
2
9
25
8 16
2
2
c)
4 b 2 x S(S a)(S b)(S = = 4 cm 4 2 x 4a 3 b x 7 x 5 144 60 4 2 x 15(15 2)(15 8)(15 10)
15
x
b
x
4
b
2 a
c
20 area 500 1000 2 x S(S a)(S b)(S c) 40 180 60 4a b 2 2 x 15.5(15.5 9)(15.5 10)(15.5 3.5) 40 1939.4375 274.91 2 Length of arc l θ a x2 r unit (a b 2 )
2
2
1575
180
b
c
+
1000
2
area
3
4a
2 S(Sx

a)(S
2
= π x a x b unit²

Area A
10 base 20 50 2 x 4 a)(S b)(S 20 1 base 500 15 x 3 x 7 x 5 144 60 b)(S 2 c) 15(15 2)(15 60 10) b 2 x 1575 360 2 2 2 unit
2
3
2
S(S
x
x
c)
b
8)(15
2
x
4
20
10
50
2 60
x
2
30 12 8 10 S b 2 3 P 3 1 x bh Base 2 Height 2 15 x 4 10 10 8 2 2 6 12 S 2 22 b x 6 x 340 4 P 2 3 180 22 1 (6 4 2 ) 2 22 2 (36 15 16) 2 x a b 60 c x 2 22 6 2 2 22

2
2
2
3
2
5
=

30
2
unit
2
bh
cm
x
1000
Base
2

2 60
3
4
5
b
4a
x
2
2
2
2 2 2 x S(S a)(S b)(S 20 1 area 500 15 x 3 3.5 12 5 S(S a)(S 2 b)(S 7 2 c) 15(15 x 4 4 2)(15 28)(15 2 10) 2 unit Height 2 2 2 x 1575 2 3.5 2 10 2 7 2 x 26 S 2 b x 7 x 2 5.1 2 32.06 cm
b
c)
S
b
x
x
x
x
7
2
144
7
7
2 3
260
10

1 2 2 3 10 9 4 base 1220 31 50 2 2 = 75.43 cm² 6.5 x 15.5 x 5.5 x 3.5

3
c)

4
x
6
S(S
5
b
2
40
1 3
b
4a
25 9 16 4 2 x S(S 2 a)(S b)(S c) 500 1 x b 4 30 12 2 x 2 8 S(S 2 2 b)(S 22 9 c) a)(S b)(S 180 1 x 2 b Base b4a 4 2 2 5 x2 6 2 1575 15 x a 2 60c b 9 10 x 2 12 6 31 2 S(S a)(S b)(S c) 15.5 x 6.5 x 5.5 x 3.5
2
2
area
1000
2
20
x
60
2

2
b
bh
P
25
10 a)(S
3 2
2
b
2 S
Height
2
10)
4a 2)(155
16

2
x
8)(15
15(1
2
b
10 base 20 4 50 2 2 x 15 x 3 x 7 x 5 S 144 60 4 4 2 3 2 4 3.5 2 10 2 5 3
4
2
2
15.5(15.5 9)(15.5 10)(15.5 3.5) 1939.4375 274.91 Length of arc l 180 θ x2 r unit (a b 2 ) 6 b θ 2 2
+
2
= 2 3 x 15
3 40
1
10

10)(15.5
2 2 2
274.91
20 area 30 12 1000 10 x2 S(S a)(S 3 P c) 1 b Perimeter (P) 9)(15.515.5(15.5 4 2 x Height 4a b 3.5) 9 60 unit 12 2 x a 31 c S b 2 a)(S 35 b)(S of c) arc l 15.5 x x2 r 5.5 x 3.5 (a b ) unit
+
2
500
1939.4375
unit
360 60
Length

8
2
x
1575
2
x

2
bh
2
b)(S
2
x
2
6.5
2 Base
2
S(S
2
2
2
5
6
2
10 base 2 20 50 S 25 b 9 16 4 2 4 4a b 3 4 3.5 2 10 2 2 2 360 2
4
22
2
12 22 22 (6 4 ) 22 (36 16) 22 22
3
x 6 x 4 cm 2 2 unit 1 3 2 3 1 unit 2 x 12 26 22 x 9 x 10 5.112 x 15 2 32.06 x 60 22 cm 6 2 4 2 22 (36 θ 22 2 22 2
2
31
2
16)
(6
2 2
2
(a
2
P

6.5

x
cm
2 7 30 12 8 7 10 9 S 2 16 b 2 b 7 15.5(15.5 x bh x 5 2 10)(15.5 3.5) x 6 7 4 x 1939.4375 274.91 a)(SS S ) 2 Length c)b)(S 2 of 2 arc l 3 2 15.5 x unit r 5.5 x x 3.5 26 2 + b ) x unit 32.06 cm
9)(15.5 Base
5.1
x2
unit b
x
2
4
S(
= 2
2 unit
Height
7 6
2
2 2

2
2 5
2
b
4a
25
2
2 10
2 3.5
2 2 4 4 2 2 4 7 7 2 7 2 360 7 2 7
10

9
31
θ
1
2
12
2
15.5(15.5 9)(15.5 10)(15.5 22 3.5) 3 1939.4375 12 (6 4 2 ) S(S 22 (36 16) r 226.5 x x 5.5 (a 3.5 x 2 + 22 )b 2
2
15.5
274.91
22
of
arc l
Length
x2
c)
2
2

5.1

2
26
25 9 16 b 4a b 4 x 5 6 x 6 x 4 cm 2 2 2 2 unit = 2 a)(S b)(S unit unit x 2 2 x x unit 32.06 cm

4 2 7 4 7 2 7 2 360 7 2 7
2
2
12
15.5(15.5 9)(15.5 22 3.5) 2 22 1939.4375 4 2 ) 274.91 22 (36 16) θ 22 r 22 (a b 2 )
10)(15.5
+
(6
2 2

x 6 x 4 cm 2 unit 2 Length of arc l = 2 x2 26 unit x x 5.1 32.06 unit
cm
unit
x
2 7 7 2 7 2 360 7 7 2
2
12 22 22 (6 4 2 ) 22 (36 16) 22 22
x 6 x 4 cm 2 2 unit 2 unit 2 x 26 = 2 x x 5.1 32.06 cm
2 7 7 2 7 2 7 7
Assignment

Circle
1 Find the circumference and area of a circle whose radius is 10.00 metre.
2 Find its diameter if the area of a circle is 330 cm².
3 Find its area if the circumference of a circle is 50 cm.
4 Find out the area and circumference of a circle of diameter is 50 cm.
5 Find its area if the circumference of a circle is 44 cm.
65
CITS : WCS - Electrical - Exercise 5