Page 76 - WCS - Electrical

WORKSHOP CALCULATION & SCIENCE - CITS

= 64.8 - 2 (12.4) cm

= 64.8 - 24.8 = 40 cm
lr 40 x 12.4
Area A = unit² =
2 2
= 248 cm²

5 Find out the length of the belt , if the arrangement of a belt is shown in the figure below.

Solution:
θ
Length l = x 2πr unit
A
360°
210° 22
= x 2 x x 30 = 110 cm
360° 7
θ
Length l B = 360° x 2πr unit

105° 22
= x 2 x x 5 = 91.7 cm
360° 7
= l + l + 2 x 214 cm
A
B
= 110 + 9.17 + 428 cm

= 547.17 cm

Hexagon

Side = a unit
Perimeter P = 6a unit

Area A = 6 x x a² units² (Area of 6 equilateral triangle)

63

CITS : WCS - Electrical - Exercise 5