Page 205 - CTS - Dress Making - TP - Volume - 1
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DRESS MAKING - CITS




           Solution
              6.5  cm x 2     =  13 cm
              13 cm x 2     =   26 cm
              26 cm + 66 cm = 92 cm

              The pattern width should be 92 cm.
           Exercises
           1  Prepare a paper model of
              –  normal pleats (pleat depth 2 cm).
              –  shallow pleats (pleat depth 2 cm/pleat width 3 cm)

              –  overlapping pleats (pleat depth 4 cm/pleat width 1 cm)
           2  Calculate the missing values (note: while calculating pleat depth, round off the final result to the next lower
              integer) (Table 1)

                                            a                            b                     c
            Pleat depth                   3 cm                         4.2 cm                 4 cm
            Pleat width                   4 cm                           -                    4 cm
            No. of pleats                   ?                            12                    ?
            Pleated section               80 cm                        62 cm                 48 cm
            Pattern width                   ?                            ?                     ?
           3  Calculate the quantity of material (fabric) required for pleated sections (“fabric allowance” in the last row refers
              to the requirement for seam allowance to join the strips) (Table 2)
                                        a                b             c              d              e

                Pleat Depth             3                4.5           3.5            4.2            2.5
                Pleat width             3                5             3              4              4
                Pleated                 168              260           144            172.2          124
                section
                Pleat length            22               12            10             48             18.5
                Width of                105              90            122            148            130
                material
                Seam                    1.5              2             3              2.5            2
                allowance
                per strip

           4  A pleated section of normal pleats has to be made. The pleated section should be 189 cm and the pleat length
              15 cm. The material available has a width of 114 cm.  A seam allowance of 2.5 cm per strip is required to join
              the strips. What is the total material requirement?
           5  A pleated section should have a width of 15.5 cm.  5 normal pleats are to be set.

              a  Calculate the pleat depth.
              b  What should be the pattern width of the material strip for the pleated section?
           6  A pattern width of 144.5 cm is available to make a pleated section. What can be the maximum width of the
              pleated section, if the pleat width should be 3.5 cm and the pleat depth should be 2.5 cm?

           7  A strip of material of 120 cm width is made into 8 normal pleats with a pleat depth of 4 cm. What will be the
              width of the pleated section?
           8  A pleated section consisting of normal pleats has a width of 95 cm, the pleat width being 5 cm, what should be
              the pattern width (ignoring the seam allowances)?


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                                        CITS : Apparel - Dress Making  - Exercise 48
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